//===-- atox.c - Ascii string parsers for LLVM libc Library -------*- C -*-===// // // A lot of this code is ripped gratuitously from glibc and libiberty. // //===----------------------------------------------------------------------===// #define isspace(x) ((x) == ' ' || (x) == '\t' || (x) == '\n') #define isdigit(x) ((x) >= '0' && (x) <= '9') #define isupper(x) ((x) >= 'A' && (x) <= 'Z') #define islower(x) ((x) >= 'a' && (x) <= 'z') #define isalpha(x) (isupper(x) || islower(x)) #ifndef ULONG_MAX #define ULONG_MAX ((unsigned long)(~0L)) /* 0xFFFFFFFF */ #endif #ifndef LONG_MAX #define LONG_MAX ((long)(ULONG_MAX >> 1)) /* 0x7FFFFFFF */ #endif #ifndef LONG_MIN #define LONG_MIN ((long)(~LONG_MAX)) /* 0x80000000 */ #endif #if 0 /* * Convert a string to a long integer. * * Ignores `locale' stuff. Assumes that the upper and lower case * alphabets and digits are each contiguous. */ long strtol(const char *nptr, char **endptr, int base) { register const char *s = nptr; register unsigned long acc; register int c; register unsigned long cutoff; register int neg = 0, any, cutlim; /* * Skip white space and pick up leading +/- sign if any. * If base is 0, allow 0x for hex and 0 for octal, else * assume decimal; if base is already 16, allow 0x. */ do { c = *s++; } while (isspace(c)); if (c == '-') { neg = 1; c = *s++; } else if (c == '+') c = *s++; if ((base == 0 || base == 16) && c == '0' && (*s == 'x' || *s == 'X')) { c = s[1]; s += 2; base = 16; } if (base == 0) base = c == '0' ? 8 : 10; /* * Compute the cutoff value between legal numbers and illegal * numbers. That is the largest legal value, divided by the * base. An input number that is greater than this value, if * followed by a legal input character, is too big. One that * is equal to this value may be valid or not; the limit * between valid and invalid numbers is then based on the last * digit. For instance, if the range for longs is * [-2147483648..2147483647] and the input base is 10, * cutoff will be set to 214748364 and cutlim to either * 7 (neg==0) or 8 (neg==1), meaning that if we have accumulated * a value > 214748364, or equal but the next digit is > 7 (or 8), * the number is too big, and we will return a range error. * * Set any if any `digits' consumed; make it negative to indicate * overflow. */ cutoff = neg ? -(unsigned long)LONG_MIN : LONG_MAX; cutlim = cutoff % (unsigned long)base; cutoff /= (unsigned long)base; for (acc = 0, any = 0;; c = *s++) { if (isdigit(c)) c -= '0'; else if (isalpha(c)) c -= isupper(c) ? 'A' - 10 : 'a' - 10; else break; if (c >= base) break; if (any < 0 || acc > cutoff || acc == cutoff && c > cutlim) any = -1; else { any = 1; acc *= base; acc += c; } } if (any < 0) { acc = neg ? LONG_MIN : LONG_MAX; } else if (neg) acc = -acc; if (endptr != 0) *endptr = (char *) (any ? s - 1 : nptr); return (acc); } /* Convert a string to an int. */ int atoi(const char *nptr) { return (int)strtol(nptr, 0, 10); } /* Convert a string to a long int. */ long int atol(const char *nptr) { return strtol(nptr, 0, 10); } #endif