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; This test makes sure that these instructions are properly eliminated.
;
; RUN: as < %s | opt -instcombine | dis | not grep 'xor '
implementation
bool %test0(bool %A) {
%B = xor bool %A, false
ret bool %B
}
int %test1(int %A) {
%B = xor int %A, 0
ret int %B
}
bool %test2(bool %A) {
%B = xor bool %A, %A
ret bool %B
}
int %test3(int %A) {
%B = xor int %A, %A
ret int %B
}
int %test4(int %A) { ; A ^ ~A == -1
%NotA = xor int -1, %A
%B = xor int %A, %NotA
ret int %B
}
uint %test5(uint %A) { ; (A|B)^B == A & (~B)
%t1 = or uint %A, 123
%r = xor uint %t1, 123
ret uint %r
}
ubyte %test6(ubyte %A) {
%B = xor ubyte %A, 17
%C = xor ubyte %B, 17
ret ubyte %C
}
; (A & C1)^(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0
int %test7(int %A, int %B) {
%A1 = and int %A, 7
%B1 = and int %B, 128
%C1 = xor int %A1, %B1
ret int %C1
}
ubyte %test8(bool %c) {
%d = xor bool %c, true ; invert the condition
br bool %d, label %True, label %False
True:
ret ubyte 1
False:
ret ubyte 3
}
bool %test9(ubyte %A) {
%B = xor ubyte %A, 123 ; xor can be eliminated
%C = seteq ubyte %B, 34
ret bool %C
}
ubyte %test10(ubyte %A) {
%B = and ubyte %A, 3
%C = xor ubyte %B, 4 ; transform into an OR
ret ubyte %C
}
ubyte %test11(ubyte %A) {
%B = or ubyte %A, 12
%C = xor ubyte %B, 4 ; transform into an AND
ret ubyte %C
}
bool %test12(ubyte %A) {
%B = xor ubyte %A, 4
%c = setne ubyte %B, 0
ret bool %c
}
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