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-rw-r--r--include/gtest/gtest-printers.h3
-rw-r--r--include/gtest/internal/gtest-internal.h38
2 files changed, 30 insertions, 11 deletions
diff --git a/include/gtest/gtest-printers.h b/include/gtest/gtest-printers.h
index cbb809f..9cbab3f 100644
--- a/include/gtest/gtest-printers.h
+++ b/include/gtest/gtest-printers.h
@@ -742,7 +742,8 @@ struct TuplePrefixPrinter<0> {
// We have to specialize the entire TuplePrefixPrinter<> class
// template here, even though the definition of
// TersePrintPrefixToStrings() is the same as the generic version, as
-// Borland C++ doesn't support specializing a method.
+// Embarcadero (formerly CodeGear, formerly Borland) C++ doesn't
+// support specializing a method template of a class template.
template <>
struct TuplePrefixPrinter<1> {
template <typename Tuple>
diff --git a/include/gtest/internal/gtest-internal.h b/include/gtest/internal/gtest-internal.h
index 947b162..cfa3885 100644
--- a/include/gtest/internal/gtest-internal.h
+++ b/include/gtest/internal/gtest-internal.h
@@ -896,21 +896,38 @@ struct IsAProtocolMessage
ImplicitlyConvertible<const T*, const ::proto2::Message*>::value> {
};
-// When the compiler sees expression IsContainerTest<C>(0), the first
-// overload of IsContainerTest will be picked if C is an STL-style
-// container class (since C::const_iterator* is a valid type and 0 can
-// be converted to it), while the second overload will be picked
-// otherwise (since C::const_iterator will be an invalid type in this
-// case). Therefore, we can determine whether C is a container class
-// by checking the type of IsContainerTest<C>(0). The value of the
-// expression is insignificant.
+// When the compiler sees expression IsContainerTest<C>(0), if C is an
+// STL-style container class, the first overload of IsContainerTest
+// will be viable (since both C::iterator* and C::const_iterator* are
+// valid types and NULL can be implicitly converted to them). It will
+// be picked over the second overload as 'int' is a perfect match for
+// the type of argument 0. If C::iterator or C::const_iterator is not
+// a valid type, the first overload is not viable, and the second
+// overload will be picked. Therefore, we can determine whether C is
+// a container class by checking the type of IsContainerTest<C>(0).
+// The value of the expression is insignificant.
+//
+// Note that we look for both C::iterator and C::const_iterator. The
+// reason is that C++ injects the name of a class as a member of the
+// class itself (e.g. you can refer to class iterator as either
+// 'iterator' or 'iterator::iterator'). If we look for C::iterator
+// only, for example, we would mistakenly think that a class named
+// iterator is an STL container.
+//
+// Also note that the simpler approach of overloading
+// IsContainerTest(typename C::const_iterator*) and
+// IsContainerTest(...) doesn't work with Visual Age C++ and Sun C++.
typedef int IsContainer;
template <class C>
-IsContainer IsContainerTest(typename C::const_iterator*) { return 0; }
+IsContainer IsContainerTest(int /* dummy */,
+ typename C::iterator* /* it */ = NULL,
+ typename C::const_iterator* /* const_it */ = NULL) {
+ return 0;
+}
typedef char IsNotContainer;
template <class C>
-IsNotContainer IsContainerTest(...) { return '\0'; }
+IsNotContainer IsContainerTest(long /* dummy */) { return '\0'; }
// EnableIf<condition>::type is void when 'Cond' is true, and
// undefined when 'Cond' is false. To use SFINAE to make a function
@@ -1009,6 +1026,7 @@ class NativeArray {
public:
// STL-style container typedefs.
typedef Element value_type;
+ typedef Element* iterator;
typedef const Element* const_iterator;
// Constructs from a native array.