summaryrefslogtreecommitdiff
path: root/lib
diff options
context:
space:
mode:
authorNick Lewycky <nicholas@mxc.ca>2011-12-28 06:57:32 +0000
committerNick Lewycky <nicholas@mxc.ca>2011-12-28 06:57:32 +0000
commit8da7ddf2d28d27e8b7fd8b7f159e2d9584bdc819 (patch)
tree0e4e9eeaaf8bd499a2b9a96632fdb1c4064319e1 /lib
parent99f9a20ba396ea35b824fe4960133446f5484e1f (diff)
downloadllvm-8da7ddf2d28d27e8b7fd8b7f159e2d9584bdc819.tar.gz
llvm-8da7ddf2d28d27e8b7fd8b7f159e2d9584bdc819.tar.bz2
llvm-8da7ddf2d28d27e8b7fd8b7f159e2d9584bdc819.tar.xz
Demystify this comment.
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@147307 91177308-0d34-0410-b5e6-96231b3b80d8
Diffstat (limited to 'lib')
-rw-r--r--lib/Transforms/Utils/SimplifyCFG.cpp21
1 files changed, 16 insertions, 5 deletions
diff --git a/lib/Transforms/Utils/SimplifyCFG.cpp b/lib/Transforms/Utils/SimplifyCFG.cpp
index 7c94bcc997..421156cdf9 100644
--- a/lib/Transforms/Utils/SimplifyCFG.cpp
+++ b/lib/Transforms/Utils/SimplifyCFG.cpp
@@ -1664,12 +1664,23 @@ bool llvm::FoldBranchToCommonDest(BranchInst *BI) {
// Merge probability data into PredBlock's branch.
APInt A, B, C, D;
if (ExtractBranchMetadata(PBI, C, D) && ExtractBranchMetadata(BI, A, B)) {
- // bbA: br bbB (a% probability), bbC (b% prob.)
- // bbB: br bbD (c% probability), bbC (d% prob.)
- // --> bbA: br bbD ((a*c)% prob.), bbC ((b+a*d)% prob.)
+ // Given IR which does:
+ // bbA:
+ // br i1 %x, label %bbB, label %bbC
+ // bbB:
+ // br i1 %y, label %bbD, label %bbC
+ // Let's call the probability that we take the edge from %bbA to %bbB
+ // 'a', from %bbA to %bbC, 'b', from %bbB to %bbD 'c' and from %bbB to
+ // %bbC probability 'd'.
//
- // Probabilities aren't stored as ratios directly. Converting to
- // probability-numerator form, we get:
+ // We transform the IR into:
+ // bbA:
+ // br i1 %z, label %bbD, label %bbC
+ // where the probability of going to %bbD is (a*c) and going to bbC is
+ // (b+a*d).
+ //
+ // Probabilities aren't stored as ratios directly. Using branch weights,
+ // we get:
// (a*c)% = A*C, (b+(a*d))% = A*D+B*C+B*D.
bool Overflow1 = false, Overflow2 = false, Overflow3 = false;